0=4w-10w^2

Solution for 0=4w-10w^2 equation:

0=4w-10w^2

We move all terms to the left:

0-(4w-10w^2)=0

We add all the numbers together, and all the variables

-(4w-10w^2)=0

We get rid of parentheses

10w^2-4w=0

a = 10; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·10·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*10}=\frac{0}{20}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*10}=\frac{8}{20}
=2/5
$